YES
Time: 0.150

Problem:
 Equations:
  
 TRS:
  g(fAC(x,y)) -> fAC(g(x),g(y))
  fAC(a(),g(g(a()))) -> fAC(g(a()),g(a()))

Proof:
 AC-KBO Processor:
  precedence:
   g > a > fAC
   weight function:
    [a] = 1,
    
    [g](x0) = 2x0,
    
    [fAC](x0, x1) = x0 + x1
   problem:
    Equations:
     
    TRS:
     
   Qed