YES
Time: 0.341

Problem:
 Equations:
  
 TRS:
  fAC(hAC(g(g(x)),x),g(fAC(x,y))) -> fAC(hAC(g(x),g(x)),fAC(g(x),y))
  hAC(fAC(x,y),x) -> fAC(hAC(x,y),x)
  fAC(g(x),y) -> g(fAC(x,y))

Proof:
 AC-KBO Processor:
  precedence:
   hAC > fAC > g
   weight function:
    [g](x0) = x0 + 4,
    
    [hAC](x0, x1) = x0 + x1 + 8,
    
    [fAC](x0, x1) = x0 + x1
   problem:
    Equations:
     
    TRS:
     
   Qed