YES
Time: 0.010

Problem:
 Equations:
  
 TRS:
  plus(x,0()) -> x
  plus(x,s(y)) -> s(plus(x,y))
  minAC(0(),y) -> 0()
  minAC(s(x),s(y)) -> s(minAC(x,y))
  maxAC(0(),y) -> y
  maxAC(s(x),s(y)) -> s(maxAC(x,y))

Proof:
 AC-RPO Processor:
  precedence:
   plus > 0 > maxAC > minAC > s
  status:
   plus:mul  
  problem:
   Equations:
    
   TRS:
    
  Qed