YES

This TRS is terminating using the deltasimple interpretation 
e(delta3) =  + 0 + 0*delta3
.(delta2, X5, X4) =  + 1*X4 + 1*X5 + 0 + 0*X4*delta2 + 0*X5*delta2 + 1*delta2
/(delta1, X3, X2) =  + 1*X2 + 1*X3 + 0 + 0*X2*delta1 + 0*X3*delta1 + 1*delta1
\(delta0, X1, X0) =  + 1*X0 + 1*X1 + 0 + 0*X0*delta0 + 0*X1*delta0 + 1*delta0
._tau_1(delta2) =  + (delta2/(1 + 0 * delta2))
._tau_2(delta2) =  + (delta2/(1 + 0 * delta2))
/_tau_1(delta1) =  + (delta1/(1 + 0 * delta1))
/_tau_2(delta1) =  + (delta1/(1 + 0 * delta1))
\_tau_1(delta0) =  + (delta0/(1 + 0 * delta0))
\_tau_2(delta0) =  + (delta0/(1 + 0 * delta0))
SUCCESS

Statistics:
Number of monomials: 302