YES

This TRS is terminating using the deltasimple interpretation 
f(delta5, X5) =  + 0*X5 + 0 + 1*X5*delta5 + 0*delta5
0(delta4) =  + 0 + 0*delta4
s(delta3, X4) =  + 0*X4 + 1 + 1*X4*delta3 + 0*delta3
cons(delta2, X3, X2) =  + 0*X2 + 0*X3 + 2 + 1*X2*delta2 + 1*X3*delta2 + 0*delta2
g(delta1, X1) =  + 0*X1 + 1 + 1*X1*delta1 + 0*delta1
h(delta0, X0) =  + 0*X0 + 0 + 3*X0*delta0 + 0*delta0
f_tau_1(delta5) =  + (delta5/(0 + 1 * delta5))
s_tau_1(delta3) =  + (delta3/(0 + 1 * delta3))
cons_tau_1(delta2) =  + (delta2/(0 + 1 * delta2))
cons_tau_2(delta2) =  + (delta2/(0 + 1 * delta2))
g_tau_1(delta1) =  + (delta1/(0 + 1 * delta1))
h_tau_1(delta0) =  + (delta0/(0 + 3 * delta0))
SUCCESS

Statistics:
Number of monomials: 239