YES

This TRS is terminating using the deltalinear interpretation 
s(delta5, X5) =  + 1*X5 + 1 + 0*X5*delta5 + 0*delta5
0(delta4) =  + 1 + 1*delta4
plus(delta3, X4, X3) =  + 1*X3 + 1*X4 + 0 + 1*X3*delta3 + 0*X4*delta3 + 0*delta3
tt(delta2) =  + 1 + 1*delta2
and(delta1, X2, X1) =  + 1*X1 + 1*X2 + 1 + 0*X1*delta1 + 1*X2*delta1 + 1*delta1
activate(delta0, X0) =  + 1*X0 + 1 + 0*X0*delta0 + 1*delta0
s_tau_1(delta5) =  + 1(delta5/(1 + 0 * delta5))
plus_tau_1(delta3) =  + 1(delta3/(1 + 0 * delta3))
plus_tau_2(delta3) =  + 1(delta3/(1 + 1 * delta3))
and_tau_1(delta1) =  + 1(delta1/(1 + 1 * delta1))
and_tau_2(delta1) =  + 1(delta1/(1 + 0 * delta1))
activate_tau_1(delta0) =  + 1(delta0/(1 + 0 * delta0))

Time: 0.010329 seconds
SUCCESS

Statistics:
Number of monomials: 129
Last formula building started for bound 1
Last SAT solving started for bound 1