YES

This TRS is terminating using the deltalinear interpretation 
c(delta3, X4) =  + 1*X4 + 0 + 0*X4*delta3 + 2*delta3
s(delta2, X3) =  + 1*X3 + 0 + 0*X3*delta2 + 1*delta2
a(delta1, X2) =  + 1*X2 + 0 + 0*X2*delta1 + 0*delta1
f(delta0, X1, X0) =  + 1*X0 + 1*X1 + 0 + 0*X0*delta0 + 0*X1*delta0 + 3*delta0
c_tau_1(delta3) =  + 1(delta3/(1 + 0 * delta3))
s_tau_1(delta2) =  + 1(delta2/(1 + 0 * delta2))
a_tau_1(delta1) =  + 1(delta1/(1 + 0 * delta1))
f_tau_1(delta0) =  + 1(delta0/(1 + 0 * delta0))
f_tau_2(delta0) =  + 1(delta0/(1 + 0 * delta0))

Time: 0.333196 seconds
SUCCESS

Statistics:
Number of monomials: 210
Last formula building started for bound 3
Last SAT solving started for bound 3