YES

This TRS is terminating using the deltarestricted interpretation 
h(delta9, X13) =  + 1*X13 + 0 + 0*X13*delta9 + 3*delta9
i(delta8, X12) =  + 1*X12 + 0 + 0*X12*delta8 + 0*delta8
s(delta7, X11) =  + 1*X11 + 0 + 0*X11*delta7 + 0*delta7
h1(delta6, X10, X9) =  + 1*X9 + 1*X10 + 0 + 0*X9*delta6 + 0*X10*delta6 + 3*delta6
0(delta5) =  + 0 + 0*delta5
h2(delta4, X8, X7, X6) =  + 1*X6 + 1*X7 + 1*X8 + 0 + 0*X6*delta4 + 0*X7*delta4 + 0*X8*delta4 + 0*delta4
j(delta3, X5, X4) =  + 1*X4 + 1*X5 + 0 + 0*X4*delta3 + 0*X5*delta3 + 3*delta3
k(delta2, X3) =  + 1*X3 + 0 + 0*X3*delta2 + 1*delta2
f(delta1, X2, X1) =  + 1*X1 + 1*X2 + 0 + 0*X1*delta1 + 0*X2*delta1 + 2*delta1
g(delta0, X0) =  + 1*X0 + 0 + 0*X0*delta0 + 1*delta0
h_tau_1(delta9) =  + 1(delta9/(1 + 0 * delta9))
i_tau_1(delta8) =  + 1(delta8/(1 + 0 * delta8))
s_tau_1(delta7) =  + 1(delta7/(1 + 0 * delta7))
h1_tau_1(delta6) =  + 1(delta6/(1 + 0 * delta6))
h1_tau_2(delta6) =  + 1(delta6/(1 + 0 * delta6))
h2_tau_1(delta4) =  + 1(delta4/(1 + 0 * delta4))
h2_tau_2(delta4) =  + 1(delta4/(1 + 0 * delta4))
h2_tau_3(delta4) =  + 1(delta4/(1 + 0 * delta4))
j_tau_1(delta3) =  + 1(delta3/(1 + 0 * delta3))
j_tau_2(delta3) =  + 1(delta3/(1 + 0 * delta3))
k_tau_1(delta2) =  + 1(delta2/(1 + 0 * delta2))
f_tau_1(delta1) =  + 1(delta1/(1 + 0 * delta1))
f_tau_2(delta1) =  + 1(delta1/(1 + 0 * delta1))
g_tau_1(delta0) =  + 1(delta0/(1 + 0 * delta0))

Time: 22.308967 seconds
SUCCESS

Statistics:
Number of monomials: 2779
Last formula building started for bound 3
Last SAT solving started for bound 3