YES
Trs:
 {f(f(a(), a()), x) -> f(f(x, f(a(), f(a(), a()))), a())}
 Comment:
  We consider a non-duplicating trs.
  BOUND:
   Automaton:
    {       a_1() -> q3,
            a_0() -> q2,
     f_1(q11, q3) -> q6,
      f_1(q6, q3) -> q2,
      f_1(q5, q5) -> q11,
      f_1(q3, q4) -> q5,
      f_1(q3, q3) -> q4,
      f_1(q2, q5) -> q6,
      f_0(q2, q2) -> q2}
   Strict:
   {}
   Qed